3x^2+3/2-x+2/2=3-x/2-(1+x^2)

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Solution for 3x^2+3/2-x+2/2=3-x/2-(1+x^2) equation: 



3x^2+3/2-x+2/2=3-x/2-(1+x^2)

We move all terms to the left:

3x^2+3/2-x+2/2-(3-x/2-(1+x^2))=0



Domain of the equation: 2-(1+x^2))!=0

We move all terms containing x to the left, all other terms to the right

-(1+x^2))!=-2

x∈R



We add all the numbers together, and all the variables

3x^2-(3-x/2-(1+x^2))-1x+1+3/2=0

We calculate fractions


3x^2-1x+1=0

a = 3; b = -1; c = +1;
Δ = b2-4ac
Δ = -12-4·3·1
Δ = -11
Delta is less than zero, so there is no solution for the equation

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